Hi,
I don't understand how the size of the structure works.
I know that an int has a size of 4 bytes, if I get the size of the struct then I have 4 bytes;
a byte has as size of 1 byte, if I get the size of the struct then I have 1 byte.
Until here everything seems fine, unless I make a structure with the two elements, the size is 8 bytes; 4+1=5 and not 8.
Here is the example :
Thanks for anyhelp ![:)]()
Br, FireFox.
I don't understand how the size of the structure works.
I know that an int has a size of 4 bytes, if I get the size of the struct then I have 4 bytes;
a byte has as size of 1 byte, if I get the size of the struct then I have 1 byte.
Until here everything seems fine, unless I make a structure with the two elements, the size is 8 bytes; 4+1=5 and not 8.
Here is the example :
#include <Constants.au3> Local Const $tagSTRUCT1 = "struct;int var1;endstruct" Local $tSTRUCT1 = DllStructCreate($tagSTRUCT1) MsgBox($MB_SYSTEMMODAL, "", "Struct1 Size: " & DllStructGetSize($tSTRUCT1)) Local Const $tagSTRUCT2 = "struct;byte var2;endstruct" Local $tSTRUCT2 = DllStructCreate($tagSTRUCT2) MsgBox($MB_SYSTEMMODAL, "", "Struct2 Size: " & DllStructGetSize($tSTRUCT2)) Local Const $tagSTRUCT3 = "struct;int var1;byte var2;endstruct" Local $tSTRUCT3 = DllStructCreate($tagSTRUCT3) MsgBox($MB_SYSTEMMODAL, "", "Struct3 Size: " & DllStructGetSize($tSTRUCT3))
Br, FireFox.